Allright, I may sound stupid on this one. How much heat (Q) is required to change 456 g of ice at -25(degrees celsius) into water at 25(degrees C). The Specific heat of ice is 2090 J/kg K, the specific heat of water is 4186 J/kg K. The latent heat of fusion of water is 33.5*10^4 J/kg. Is this just going to be Qwater+Qice+Qlatent? Where Qlatent is m*L?