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Quick question. Latent heat problem.

  1. May 3, 2004 #1
    Allright, I may sound stupid on this one.
    How much heat (Q) is required to change 456 g of ice at -25(degrees celsius) into water at 25(degrees C). The Specific heat of ice is 2090 J/kg K, the specific heat of water is 4186 J/kg K. The latent heat of fusion of water is 33.5*10^4 J/kg.

    Is this just going to be Qwater+Qice+Qlatent? Where Qlatent is m*L?
  2. jcsd
  3. May 3, 2004 #2
    [tex]Q = cm\Delta T[/tex]


    [tex]Q = mH_f[/tex]

    I think you have the right idea, but your notation is a little awkward.

  4. May 3, 2004 #3
    Thanks cookiemonster. I appreciate the help.
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