a hot air balloonist, rising vertically with a constant velocity of magnitude 5m/s releases a sandbag at an instant when the balloon is 40m above the ground. after it is released, the sandbag is in free fall. a) compute position at .250s i solved it and got ~ 40.9m, which is correct. but why is it +.9m above when it was dropped when the position of the balloonist was 40m? shouldn't it be -.9m? is it b/c even though the sandbag was dropped at the instant the balloonist was at 40m, the position increased due to the velocity which includes a rise in position within that .250s that they were asking for?