- #1
Tonyt88
- 62
- 0
You have a cylinder (with radius R) rolling horizontally on a surface with kinetic friction of u(mu). I understand that the horizontal acceleration is u*g b/c:
ma = u*(mg)
a = u*g
and then you have
a = r (alpha_z)
thus I'd figure alpha_z is just u*g/R, but the book gives a solution of:
-2 u*g/R
Basically, what's the reasoning?
ma = u*(mg)
a = u*g
and then you have
a = r (alpha_z)
thus I'd figure alpha_z is just u*g/R, but the book gives a solution of:
-2 u*g/R
Basically, what's the reasoning?