- #1
sebmista
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The weight of a 0.7 kg object of charge Q is just balanced by another object of equal but opposite charge fixed to a support 132 cm above it. What is the magnitude of the charge Q (in μC)? [Note that 1 μC=1x10-6C.]
Ok I know how to do this but it says I'm wrong... am I really wrong or is the computer wrong?
.7kg times gravity = 6.86N
The force between these two objects would be coulombs law.
F= Ke (QQ/r^2) set force = to 6.86 and solve for Q
It gave me .36443 micro C.
What do you guys get?
Ok I know how to do this but it says I'm wrong... am I really wrong or is the computer wrong?
.7kg times gravity = 6.86N
The force between these two objects would be coulombs law.
F= Ke (QQ/r^2) set force = to 6.86 and solve for Q
It gave me .36443 micro C.
What do you guys get?