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Homework Statement
How would you differentiate, (v^3-2v*squareroot v)?
Homework Equations
The Attempt at a Solution
would it look like....3v^2 - v^-1/2 ?
The 3v^2 part is correct! But how did you obtain v^-1/2??would it look like....3v^2 - v^-1/2 ?
Ah, see that's the thing how to you differentiate a square root? I have no idea?The 3v^2 part is correct! But how did you obtain v^-1/2??
Well okay, I wanted to see if by understanding how to derive squareroot v, I could understand a much bigger problem.Well, [tex]\sqrt{x}=x^{1/2}[/tex], so you just need to apply the power rule!
But the problem is that you don't only have a square root, you have [tex]v\sqrt{v}[/tex]. To derive this, you have to apply the chain rule. (or if you know your algebra, you could notice that [tex]v^{3/2}=v\sqrt{v}[/tex] and immediately apply the power rule)...
I don't think so, I haven't tried that I know the answer...because it is....(2v-1)/squareroot2Can't you just cancel v from the numerator and denominator??
No, you don't have to use the quotient rule if you simplify this first.y=(v^3 - 2v*square rootv)/ v
and I have to differentiate it, I know I have to use the quotient rule and I have tired but the dang square root is cause me problems.
How can I vote you to be a life saver? Thank you so much, for some reason my teacher told me I HAD to use the quotient rule and I guess that blocked me to thinking of other ways! Thank you so much, your a life saver!No, you don't have to use the quotient rule if you simplify this first.
[tex]y = \frac{v^3 - 2v\sqrt{v}}{v} = v^2 - 2\sqrt{v} = v^2 - 2v^{1/2}[/tex]
Well, I meant that he didn't really give us clues as to have other ways of solving them, your were a great help. I still had to differentiate the final answer which you gave me, but I was able to do that no problem. Thank you anyways, again you did help me.Well, if the instructions are that you have to use the quotient rule, then I haven't been any help at all. If so, I would write the numerator as v^{3} - 2v^{3/2}.