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Quick Question

  1. Jan 26, 2005 #1
    A ball is thrown straigh up, from height of 25 m above the ground, at a speed of 11 m/s.
    The first question is what is the max. height of the ball above the ground.
    I got that one it's like 31m. But there was another question after that that asks how long is the ball in the air. What equation must I use to find this out?
     
  2. jcsd
  3. Jan 26, 2005 #2
    When does the ball 'stop' being in the air?
     
  4. Jan 26, 2005 #3
    well first find the time taken to reach the max ht. double this time it is the time taken for the ball to reach the ht it was thrown from(25m ) at this pt the ball has a speed of 11m/s use s =ut+4.9t^2 to find this t2 add this to t1 and that is the time taken to reach the ground. to find time to reach max ht use v = u+at.
     
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