1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Quick Question

  1. Jan 26, 2005 #1
    A ball is thrown straigh up, from height of 25 m above the ground, at a speed of 11 m/s.
    The first question is what is the max. height of the ball above the ground.
    I got that one it's like 31m. But there was another question after that that asks how long is the ball in the air. What equation must I use to find this out?
  2. jcsd
  3. Jan 26, 2005 #2
    When does the ball 'stop' being in the air?
  4. Jan 26, 2005 #3
    well first find the time taken to reach the max ht. double this time it is the time taken for the ball to reach the ht it was thrown from(25m ) at this pt the ball has a speed of 11m/s use s =ut+4.9t^2 to find this t2 add this to t1 and that is the time taken to reach the ground. to find time to reach max ht use v = u+at.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook