- #1

ccb056

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"Two vectors, F and G, act concurrently and simultaneously on a particle. If F=20m at 30 degrees and the resultant, R, of the vectors is 50m at 45 degrees, the angle of force G is"?

thanks for making me feel stupid :D

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- Thread starter ccb056
- Start date

- #1

ccb056

- 8

- 0

"Two vectors, F and G, act concurrently and simultaneously on a particle. If F=20m at 30 degrees and the resultant, R, of the vectors is 50m at 45 degrees, the angle of force G is"?

thanks for making me feel stupid :D

- #2

ccb056

- 8

- 0

cough ?

- #3

ccb056

- 8

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this is the right forum, no?

- #4

HallsofIvy

Science Advisor

Homework Helper

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"Two vectors, F and G, act concurrently and simultaneously on a particle. If F=20m at 30 degrees and the resultant, R, of the vectors is 50m at 45 degrees, the angle of force G is"?

Did you read "Read this before posting" before posting?

Since we don't want to make you feel stupid, we ask that you make some effort and show us what you have done- so that we will know that we are not just doing your homework for you and also so that we will have a better idea of what kind of help you need.

I know at least two very different methods of solving this. I DO NOT know which is appropriate for you.

- #5

ccb056

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i don't really understand the problem, i can't make a picture of what they are expressing, if you could show me a pictue of the problem, i think ill be able to solve it

the reason I ask, is because I've got an exam over some general physics, and this is a example problem the teacher gave me, and i didnt know where to start

thanks

- #6

arcnets

- 508

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Label the origin as O.

Mark a point F, so that:

- the line OF is at an angle of 30° WRT the x-axis.

- the distance OF is 20.

Mark another point R, so that

- the line OR is at an angle of 45° WRT the x-axis.

- the distance OR is 50.

BTW, it's convention to have angles counter-clockwise.

They want you to find the point G, so that OFRG is a parallelogram. They want to know the angle of the line OG WRT the x-axis.

OK?

- #7

ccb056

- 8

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thanks alot, very helpful

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