[tex]\frac{n}{2^{n+2}}[/tex](adsbygoogle = window.adsbygoogle || []).push({});

I know it's monotonic decreasing, a sub n < a sub n+1 and so has an upper bound of 1/8.

Can you then use L'Hopital's rule to determine that the sequence converges to 0, it's lower bound?

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# Homework Help: Quick sequence question

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