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  1. Sep 8, 2004 #1
    1. A speed skater moving across frictionless ice at 8.20 hits a 4.60-m-wide patch of rough ice. She slows steadily, then continues on at 5.30 .
    SLC: I am assuming that Vf = 5.3 m/s ; Vi = 8.2 m/s ; d = 4.60 m ; a =? ; t = ?.
    Can you get me started with a correct forumula? I am fairly certain I can get the answer from there.

  2. jcsd
  3. Sep 8, 2004 #2
    Vf^2 = Vi^2 + 2a(d)

    d = Vi (t) + .5at^2

    These are two of the general equations for kinematics.
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