1. The problem statement, all variables and given/known data A uniform ladder is 10m long and weighs 400 N. It rests with its upper end against a frictionless vertical wall. Its lower end rests on the ground and is prevented from slipping by a peg driven into the ground. The ladder makes a 30◦ angle with the horizontal. The magnitude of the force exerted on the peg by the ladder is: A. zero B. 200N C. 400N D. 470N E. 670N 2. Relevant equations torque = r x F 3. The attempt at a solution First I identified the forces. So normal force, frictional force, weight, and force from the wall and force from the peg which acts horizantally. Basically, I just took moments about the base of the ladder. I got -400(5cos30) + 5Fw = 0. Then I solved for Fw getting 346. Then I set all x forces equal to each other. Getting 346 = Fpeg + Ffrictional. And I got stuck lol. I don't know if there's no frictional force at all and that the peg is acting in place of it or if it's the sum of them together that provides the x component.