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Quick Thermo question

  1. Dec 5, 2004 #1
    For a device operating at steady state, is the change in entropy (S2-S1) equal to 0?
    If it is equal to 0, then why doesn't the s2-s1=s(degree)(T2)-s(degree)(T1) - R ln (p2/p1) equation yield 0?

    I'm confused on this point...
    Any help greatly appreciated!
     
  2. jcsd
  3. Dec 6, 2004 #2

    Clausius2

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    Gold Member


    That's False. Where have you seen it?
     
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