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Quick trig identity question

  1. Nov 18, 2008 #1
    Does
    CSC([tex]\pi[/tex]/2 - x) = SinX OR 1 / SinX?

    What about
    CSC2([tex]\pi[/tex]/2 -x)?

    Does
    COT([tex]\pi[/tex]/2 + x) = -TanX or 1/-TanX?
     
  2. jcsd
  3. Nov 18, 2008 #2
    csc ( \\pi - x) = secx
     
  4. Nov 18, 2008 #3

    Dick

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    It does NOT. HelloMotto, don't you have some kind of opinion on a multiple choice question like this? You could at least substitute some values in for x.
     
  5. Nov 18, 2008 #4
    Whoops, I meant csc(pi/2 - x) = secx
    It was a mistake on my behalf.
     
  6. Nov 18, 2008 #5

    Dick

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    Now I'll believe that one. It's all up to HelloMotto now.
     
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