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Quick Trig. Question

  1. Nov 8, 2011 #1
    1. The problem statement, all variables and given/known data
    I am working through a calc 2 problem. I managed to get here without really completely understanding trig. There was a point in the problem where θ=Tan-1(-2/2) = -Pi/4. How does this work?

    2. Relevant equations
    I do not know any relevant equations


    3. The attempt at a solution
    I really have no clue. I have done research countless times.
     
  2. jcsd
  3. Nov 8, 2011 #2

    symbolipoint

    User Avatar
    Homework Helper
    Education Advisor
    Gold Member

    For purposes of the Inverse Tangent, the Tangent function is restricted to the angle values from negative pi/2 to positive pi/2. A tangent of (-2/2) is the same as the tangent of (-1), and just relating this to the unit circle, this ange is -π/4.
     
  4. Nov 8, 2011 #3

    Mark44

    Staff: Mentor

    I would advise you to spend some time reviewing basic trigonometry, especially in relation to the trig functions and their inverses. If you are trying to work through integrals without a solid understanding of trig, you will really have a hard time, particularly when it comes to trig substitutions.

    Some time invested in reviewing your old precalc book would really pay off. Alternatively, there are many helpful videos about a variety of topics in math at khanacademy.org. A good place to start would be http://www.khanacademy.org/#trigonometry.
     
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