- #1
dori1123
- 11
- 0
Show that if H is a normal subgroup of G of prime index p, then for all subgroups K of G, either
(i) K is a subgroup of H, or
(ii) G = HK and |K : K intersect H| = p.
(i) K is a subgroup of H, or
(ii) G = HK and |K : K intersect H| = p.