• Support PF! Buy your school textbooks, materials and every day products Here!

R-C circuit

  • #1

Homework Statement


upload_2018-8-18_22-13-30.png


Homework Equations


upload_2018-8-18_22-14-42.png


The Attempt at a Solution


39504851_2244785085535615_6189799527172538368_n.jpg

I proved part a)
Can you please check if part b) is correct?
I don't know what to do in part c)
 

Attachments

Answers and Replies

  • #2
Charles Link
Homework Helper
Insights Author
Gold Member
4,522
1,926
For part (c), the current is the same everywhere in a series circuit, and can be computed by ## i=\frac{dq}{dt} ## when there is a capacitor in the circuit, where ##q ## is the charge on the capacitor. This can also be used for part b. (Your part (b) is incorrect). Alternatively, you could compute ## V_R=\mathcal{E}-V_C ## where ## V_c=\frac{q}{C} ##.
 
Last edited:
  • #3
Chandra Prayaga
Science Advisor
649
148
I get the feeling that you are trying to use some equations without fully understanding them.
1. Why do you think the equation I = q/t is right?
2. I do not see your attempt at part (a). That part is crucial to the understanding of the problem.
3. I do not understand your first value for q, which looks like q = 1 10^(-6) . 10
4. Then there is a second value for q = 3.93 10^(-6) C. Why did you use the same symbol for two different values?
5. The way you got the value for I = 0.08 A is wrong. That equation for I is not valid.
 

Related Threads on R-C circuit

  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
0
Views
957
  • Last Post
Replies
5
Views
6K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
2
Views
3K
Replies
5
Views
1K
Replies
3
Views
2K
Replies
1
Views
602
  • Last Post
Replies
2
Views
2K
Top