# R-C network analysis (AC)

1. Apr 1, 2014

### zealeth

1. The problem statement, all variables and given/known data

Compute values for R and C such that the total series impedance Z=500$\angle$(-36.1o) when f=10kHz.

2. Relevant equations

ω=2$\pi$f
KVL
ZC = -j*(1/(ωC)) = 1/(jωC) where j=$\sqrt{-1}$

3. The attempt at a solution

Seems like a pretty straightforward problem, I seem to be missing an equation somewhere but not sure what else I could use here.

ω=2*$\pi$*10*103 = 62832 rad/s
Zeq=500$\angle$(-36.1o) = R - j/(ωC) = R - j/(62832*C)

And here I am left with 1 equation and 2 variables, any ideas on what else I could use to solve this problem?

2. Apr 2, 2014

### Staff: Mentor

Actually you're left with two equations, each in one variable. Note that the impedance has two terms, one real and one imaginary. The real and imaginary components are separate. For example, the real part of the impedance (the resistance) is independent of frequency.