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R-C network analysis (AC)

  1. Apr 1, 2014 #1
    1. The problem statement, all variables and given/known data

    Compute values for R and C such that the total series impedance Z=500[itex]\angle[/itex](-36.1o) when f=10kHz.


    2. Relevant equations

    ZC = -j*(1/(ωC)) = 1/(jωC) where j=[itex]\sqrt{-1}[/itex]

    3. The attempt at a solution

    Seems like a pretty straightforward problem, I seem to be missing an equation somewhere but not sure what else I could use here.

    ω=2*[itex]\pi[/itex]*10*103 = 62832 rad/s
    Zeq=500[itex]\angle[/itex](-36.1o) = R - j/(ωC) = R - j/(62832*C)

    And here I am left with 1 equation and 2 variables, any ideas on what else I could use to solve this problem?
  2. jcsd
  3. Apr 2, 2014 #2


    User Avatar

    Staff: Mentor

    Actually you're left with two equations, each in one variable. Note that the impedance has two terms, one real and one imaginary. The real and imaginary components are separate. For example, the real part of the impedance (the resistance) is independent of frequency.
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