- #1
luckis11
- 272
- 2
My question is the title of the thread.
Sorry, and this one too:
f’’(t)=GM/((Α-f(t))^2
Sorry, and this one too:
f’’(t)=GM/((Α-f(t))^2
Last edited:
Mark44 said:Integrate twice with respect to t to get r(t).
Why? Knowing an answer without knowing how to get it is useless.luckis11 said:I want the answer, not the method to solve it. Thanks though.
That's not how this forum works. Instead, you show that you have made an effort and we help you with it.luckis11 said:I want the answer, not the method to solve it. Thanks though.
Mark44 said:That's not how this forum works. Instead, you show that you have made an effort and we help you with it.
mysol = NDSolve[{Derivative[2][y][x] == -2/y[x]^2, y[0] == 2,
Derivative[1][y][0] == 0}, y, {x, 0, 2}]
lowy = N[y[1] /. mysol]
mytable = Table[
{(Sqrt[-1 + 2/y]*y + ArcTan[(Sqrt[-1 + 2/y]*(-1 + y))/
(-2 + y)])/Sqrt[2] + Pi/(2*Sqrt[2]), y},
{y, lowy[[1]], 2, 0.01}]
lp1 = ListPlot[mytable]
pp1 = Plot[y[x] /. mysol, {x, 0, 2}]
Show[{pp1, lp1}]
The formula represents the second derivative of the position function "r(t)" for an object in circular motion, where R represents the centripetal acceleration, G is the universal gravitational constant, M is the mass of the central body, and r(t) is the distance between the object and the central body at time t.
The distance "r(t)" can be calculated by taking the square root of the negative value of the ratio between the universal gravitational constant (G) and the second derivative of the position function (R’’(t)). This represents the inverse relationship between the acceleration and the distance, where the distance decreases as the acceleration increases.
The minus sign represents the direction of the centripetal acceleration, which always points towards the center of the circular motion. This indicates that the acceleration is always directed towards the central body, regardless of the direction of motion of the object.
The mass of the central body (M) has a direct relationship with the acceleration (R’’(t)) in the formula, where a larger mass will result in a larger acceleration and a smaller mass will result in a smaller acceleration. This is due to the fact that the gravitational force between two objects is directly proportional to their masses.
No, the formula is specifically for an object in circular motion. For non-circular motion, the distance (r(t)) would change as the object moves, and the formula would need to be modified to account for this change in distance.