Race car velocity problem

  • Thread starter the_d
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  • #1
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A race car moves such that its position fits the relationship
x(t) = (4.4 m/s) t + (0.91 m/s^3) t^3 (yes cubed)
where x is measured in meters and t in seconds.Approximate the instantaneous velocity at t = 2.6 s, using a time interval of 0.2 s. Answer
in units of m/s.

i am just stuck and dont even know where to start
 

Answers and Replies

  • #2
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ok, the velocity is
[tex] \frac{\Delta x} {\Delta t} [/tex]

now the question come down to what is delta x and delta t
hope you can come out the answer
 
  • #3
dextercioby
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Take the time origin [itex] t_{0} [/itex] to be 0.

Daniel.
 
  • #4
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but what is Xo and X?
 
  • #5
dextercioby
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Kay.
[tex] x_{0}=x(t_{0})=x(0) [/tex]

[tex] x=x(2.6) [/tex]

Daniel.
 
  • #6
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ok i got all that, but what is still confusing me is the "time interval" what do i do with that
 
  • #7
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dextercioby said:
Kay.
[tex] x_{0}=x(t_{0})=x(0) [/tex]

[tex] x=x(2.6) [/tex]

Daniel.

what is the time interval for???
 

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