The question reads: The optical rotation of pure pencicillin G is +206 degrees. A sample of pencillin G was found to have an optical rotation of +103 degrees. Calculate the enantiomeric excess (ee) in the mixture.(adsbygoogle = window.adsbygoogle || []).push({});

I did so by: 103/203 x 100 = 50%

Here is where I am lost:

Next calculate the precent composition of the (+) enantiomer.

What the heck is that? I know it is a mole fraction but how do I know what to plug in. Any ideas? :uhh:

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# Racemic Mixture

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