- #1

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Anyways ease on the flamming I am just trying to learn or better understand what I have learned. I feel like I understood it before but have forgotten since I never reviewed it after the test about 5 months ago.

Thanks.

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- Thread starter Mozart
- Start date

- #1

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Anyways ease on the flamming I am just trying to learn or better understand what I have learned. I feel like I understood it before but have forgotten since I never reviewed it after the test about 5 months ago.

Thanks.

- #2

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http://mathforum.org/library/drmath/view/55522.html

The other articles will probably be useful as well.

http://mathforum.org/library/drmath/sets/high_logs.html

- #3

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Thank you!

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Suppose I have a function that looks like b^x.

For what value of b will d[b^x]/dx = b^x?

Or, for what value of b will the derivative of our function equal the function itself?

One can solve this equation for b and discover that b=~2.718. [*]

This property is so extremely useful that it pops up all the time. This is why it was given a dedicated constant.

* 2.718 is only an approximation, as I am sure you know. If you want to know what b, and therefore e, really is then follow this link http://www.answers.com/topic/e-mathematical-constant and be sure to click on irrational and transcendental once you are done reading the page.

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Mozart said:Thank you!

My pleasure.

- #6

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Consider:

ln x = y

Most people would read this aloud as "natural log of x equals y".

But there is a better way to "sound it out". Try this -

"The power which you must raise e to obtain x is y". It helps.

After all, in this case, e^y = x, so you can easily remember what a log is by reading it aloud that way - what it really represents.

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- #8

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My first college instructor liked to emphatically put it this way: [tex]e^{lnX}[/tex] says that e is the power to which ln(X) must be raised to give X!

Is that helpful?

Is that helpful?

Last edited:

- #9

cepheid

Staff Emeritus

Science Advisor

Gold Member

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robert Ihnot said:My first college instructor liked to emphatically put it this way: [tex]e^{lnX}[/tex] says that e is the power to which ln(X) must be raised to give X!

Is that helpful?

No it's not, because it should read: lnx is the power to which e must be raised to give x!

:tongue2:

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