- #1
courtrigrad
- 1,236
- 2
Find the required angular velocity of an ultracentrifuge in [itex] \frac{rev}{min} [/itex] for the radial acceleration of a point 1.00 cm from the axis to equal 400,000g (that is, 400,000 times the acceleration of gravity.)
So [tex] a_{rad} = (\omega)^{2}r [/tex]. [tex] 400,000g = \omega^{2}(0.01 m) [/tex]. Would I just solve for [tex] \omega [/tex]? [tex] \omega [/tex] would be in m/s? Then to convert to rev/min, you use the fact that [tex] 2\pi(0.01 m) [/tex] equals 1 revolution?
Would this be the correct way to solve this problem?
Thanks
[
So [tex] a_{rad} = (\omega)^{2}r [/tex]. [tex] 400,000g = \omega^{2}(0.01 m) [/tex]. Would I just solve for [tex] \omega [/tex]? [tex] \omega [/tex] would be in m/s? Then to convert to rev/min, you use the fact that [tex] 2\pi(0.01 m) [/tex] equals 1 revolution?
Would this be the correct way to solve this problem?
Thanks
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