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Radial acceleration

  1. Oct 22, 2008 #1
    Consider a planet of radius 5.53X10^6 m with a rotation period of 24.3 hours. Compute the radial acceleration of a point on the surface of the planet at the equator due to its rotation about its axis.

    What is the Radial Acceleration.

    I found out that the formula for radial acceleration is v^2/r but I don't know how to make the problem fit into it!
     
  2. jcsd
  3. Oct 22, 2008 #2

    Dick

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    How do you find v? How far does a point on the equator travel in 24.3 hours? v=distance/time.
     
  4. Oct 22, 2008 #3
    i don't get the distance. the only distance i get is the radius.
     
  5. Oct 22, 2008 #4

    Dick

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    A point on the equator rotates around the planet once in 24.3 hours. What's the circumference of the planet? It is related to r.
     
  6. Oct 22, 2008 #5
    ooo so then v = 2pi(r)/t
    and then I can plug it in the original formula for the radial acceleration right?
     
  7. Oct 22, 2008 #6
    thank you so much I got it!
     
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