1. The problem statement, all variables and given/known data The 3 kg collar B slides on the frictionless arm AA'. The arm is attached to drum D and rotates about O in a horizontal plane at the rate dθ/dt = 0.75t, where dθ/dt and t are expressed in rad/s and seconds, respectively. As the arm-drum assembly rotates, a mechanism within the drum releases cord so that the collar moves outward from O with a constant speed of 0.5 m/s. Knowing that at t = 0, r = 0, determine the time at which the tension in the cord is equal to the magnitude of the horizontal force exerted on B by arm AA'. 2. Relevant equations Fr = m(d2θ/dt2 - r(dθ/dt)2) Fθ = m(rd2θ/dt2 + 2(dr/dt)(dθ/dt)) ƩF = ma 3. The attempt at a solution Fr = -T r = (0.5 m/s)t dr/dt = 0.5 m/s d2r/dt = 0 m/s2 dθ/dt = (0.75 m/s)t d2θ/dt = 0.75 m/s2 Fr = 3 kg(0 - 0.5t(0.75t)2) Fr = -0.844t3 Fθ = 3 kg(0.5t(.75) + 2(0.5)(0.75t)) Fθ = 3.375t Now if Fr = -T then I can substitute -T for Fr. Therefore T = 0.844t3 I'm not sure where to go after this one.. I need to somehow solve for t I know that but I'm just not sure because I have two equations and three unknowns. Thanks ahead of time for any help.