1. The problem statement, all variables and given/known data Carefully study the following plot of electric field E in N/C versus distance r in m and answer the questions that follow. The electric field is directed radially outward, and the variation of E with r is independent of direction. [/b] For each statement, select "True" or "False".[/b] The work done by you to bring a point negative charge from infinity to A is positive.[/b] The Electric field falls off as 1/r for r greater than R.[/b] The force on a negative charge placed at A points radially towards the origin.[/b] All points at a given distance 'd' from the origin are at the same electrostatic potential.[/b] The above electric field could be that due to a negatively charged spherical shell.[/b] The electric potential is constant for r less than R. [/b] 2. Relevant equations Va-Vb=∫Edl E=Kq/r^2 3. The attempt at a solution First i figured that since the electric field is point outward the the charge must be positive to accelerate positive charges outward.[/b] Therefore the work to bring a negative charge from infinity to the origin would be positive the force is "pulling the negative charge in towards the origin.[/b] It sure looks like the graph has a 1/r curve after r > R.[/b] If the electric field points outward then a negative charge would accelerate inward. therefore the force on the negative charge is inward.[/b] I thought about the equi-potential line at 'd' the voltage should be the same at any point at the same distance away from the charge.[/b] The electric field could not be due to a negative charge, If it were the E-Field would point in instead of out.[/b] Since electric field is the derivative of Electric Potential and the E-Field is zero for the given range the potential must be constant. Where am i going astray here? I was given the hint: "Remember that the Electric Field is the negative spatial derivative of the potential. Look up the definition of electric potential and work done against an electric field. "