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1. Dec 22, 2017

Thank you.

Can anyone else please type out their worked solution? This type of question might come up in my exam and I still don't understand how to do it. I need to know how to do it step by step.

2. Dec 22, 2017

### kuruman

Sorry, forum rules expressly prohibit what you ask. You will find them here if you have not already seen them.
Under item 8:
"Complete solutions can be provided to a questioner after the questioner has arrived at a correct solution. If the questioner has not produced a correct solution, complete solutions are not permitted, whether or not an attempt has been made."

Read post #20 by @gleem and see if you can reproduce the numbers show.

3. Dec 28, 2017

Hi PSR, why is 84 divided by GBq in the first line? Is it a given value in a text book?

4. Dec 28, 2017

Could you tell me the website / book which gives the specific dose rate (84sv/h/GBq). Thank you

5. Dec 28, 2017

### PSRB191921

See my post 15
"The dose for Cs137 is due to the 662 keV
You know that H=1.5E-10×A×i×E (in mSv/h) with A in Bq , E in MeV and i=.85 See, for example chapter 4 of
http://www.springer.com/us/book/9783319486581 "
84 microSv/h/GBq means 84 microSv/h for 1 GBq at one meter

6. Dec 29, 2017

7. Dec 29, 2017

### kuruman

First you need to convert 662 keV to MeV in the format 6.62×10y MeV. (What should y be?). Then you find the closest value in the Table and interpolate.
Be sure to read how to use the value that you found here.
https://physics.nist.gov/PhysRefData/XrayMassCoef/chap2.html

8. Dec 29, 2017

For 6.62x10-1 the closest value is 6.00000E-01, which gives a reading of 1.248E-01 for u/p. Not sure what to do now.

9. Dec 30, 2017