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Radiation loss

  1. Apr 14, 2005 #1
    I analyzed the chimney gas from a 70 kWboiler burning pellets. I found the temperature to be 140C, the CO2 value was 8%, and the room temp was 22C. Is it possible from this to calculate the boilers radiation loss? If not, what other information do I need? I used Siegert's formula to find the chimney loss by [tex]0,8\frac{140-22}{8}=11,8[/tex] where 0,8 is a constant used for pellets.
  2. jcsd
  3. Apr 15, 2005 #2


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    You can actually calculate an upper bound on the heat radiated by the boiler if you knew the temperature in the boiler. Not all of this radiation will contribute to a loss, and that fraction will depend on the construction (materials and geometry) of the boiler.
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