Radiation Physics Homework: Kc air, Energy Transferred, Particles Transmitted

MeV. So, the energy imparted is 3.5 MeV + 1.5 MeV = 5 MeV.3. This problem involves a plane-parallel monoenergetic beam of 10^12 uncharged particles per second incident on a layer of material. We are given the thickness of the material, its density, and the mass attenuation coefficient for three different values. We are asked to calculate the number of primary particles transmitted in 1 minute for each value of the mass attenuation coefficient and compare it with the approximation. The mass attenuation coefficient is a measure of how much a material attenuates (reduces) the intensity of a beam of
  • #1
marchhansen
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Homework Statement



1. What is (Kc)air in Gy at a point in air where X = 47 roentgens?

2. An electron enters a volume V with a kinetic energy of 4 MeV and carries 0.5 MeV of that energy out of V when it leaves. While in the volume it produces a bremsstrahlung x-ray of 1.5 MeV which escapes from V. What is the contribution of this event to:

a. The energy transferred?
b. The net energy transferred?
c. The energy imparted?

3. A plane-parallel monoenergetic beam of 10^12 uncharged particle per second is incident perpendicularly on a layer of material 0.02 m thick, having a density ρ = 11.3 x 10^3 kg/m3. For values of the mass attenuation coefficient μ/ρ = 1 x 10^-3, 3 x 10^-4, and 1 x 10^-4 m2/kg, calculate the number of primary particles transmitted in 1 minute. Compare in each case with the approximation; Give the percentage errors.


Homework Equations



Totally no idea

The Attempt at a Solution



Please give me a hint on how to work on these. These are representative problems, I will work on many similar problems based on the answer to this one. Please explain in detail. I need to understand it more than to answer it.

The answer are as follows

1. [0.412 Gy]

2.
a. [0]
b. [0]
c. [2.0 MeV]

3. [4.786 x 1013, 5.607 x 1013 , 5.866 x 1013; 4.644 x 1013 , 5.93 x 1013 , 5.8644 x 1013; 3%, 0.25%, 0.03%]
 
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  • #2



Hi, it seems like you are struggling with these problems. Let's break them down and go through them step by step.

1. For this problem, we are given a point in air where the exposure is 47 roentgens (X = 47). We are asked to find the air kerma (Kc) at this point.

The air kerma is a measure of the energy deposited in a unit mass of air. We can use the equation Kc = X * Kair, where Kair is the air kerma coefficient. The air kerma coefficient is a constant value that depends on the type of radiation and the energy of the radiation.

To find Kc, we need to first determine the air kerma coefficient for this radiation. Without knowing the type of radiation, we cannot calculate Kair. So, unfortunately, we cannot solve this problem without more information.

2. This problem involves an electron entering a volume V with a kinetic energy of 4 MeV and carrying 0.5 MeV out of the volume. While in the volume, it produces a bremsstrahlung x-ray of 1.5 MeV which escapes from the volume. We are asked to find the contribution of this event to the energy transferred, the net energy transferred, and the energy imparted.

Let's start by defining some terms. The energy transferred is the amount of energy that is transferred from the electron to the material in the volume. The net energy transferred is the difference between the initial and final energies of the electron. And the energy imparted is the sum of the energy transferred and the energy of the bremsstrahlung x-ray.

a. To find the energy transferred, we need to calculate the energy lost by the electron. Since it enters the volume with 4 MeV and leaves with 0.5 MeV, it loses 3.5 MeV of energy. Therefore, the energy transferred is 3.5 MeV.

b. The net energy transferred is the difference between the initial and final energies of the electron. Since the electron loses 3.5 MeV of energy, the net energy transferred is 4 MeV - 0.5 MeV = 3.5 MeV.

c. The energy imparted is the sum of the energy transferred and the energy of the bremsstrahlung x-ray. The energy transferred is 3.5 MeV and the energy of
 

What is radiation physics?

Radiation physics is a branch of physics that deals with the study of the properties and effects of radiation, including both electromagnetic and particle radiation.

What is Kc air in radiation physics?

Kc air, also known as air kerma coefficient, is a measure of the energy transferred to air by ionizing radiation per unit mass. It is used to calculate the absorbed dose in air, which is an important factor in radiation protection.

How is energy transferred in radiation physics?

Energy can be transferred in radiation physics through two main mechanisms: ionization and excitation. Ionization occurs when an atom or molecule loses an electron, while excitation occurs when an electron is temporarily elevated to a higher energy state.

What is the role of particles transmitted in radiation physics?

Particles transmitted, also known as secondary particles, refer to the particles that are produced as a result of the interaction between radiation and matter. These particles can cause further damage and must be taken into account in radiation protection.

What are some common applications of radiation physics?

Radiation physics has various applications, including medical imaging and therapy, nuclear power generation, and industrial radiography. It is also used in research to study the properties and behavior of radiation.

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