- #1

brilapwnzall

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## Homework Statement

The filament of a light bulb has a temperature of 3.2*10^3°C and radiates 59 watts of power. The emissivity of the filament is 0.38. Find the surface area of the filament.

## Homework Equations

[tex]\Delta[/tex]Q/[tex]\Delta[/tex]T=e[tex]\sigma[/tex]AT^4

[tex]\sigma[/tex]=5.67*10^-8

## The Attempt at a Solution

59=(.38)(5.67*10^-8)(A)(3.2*10^3)^4

Use needed Algebra to solve for A and I get 2.61e-5, but it's not the right answer.

Can someone please tell me what I am doing wrong?