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Radiation problem!

  • #1

Homework Statement


The filament of a light bulb has a temperature of 3.2*10^3°C and radiates 59 watts of power. The emissivity of the filament is 0.38. Find the surface area of the filament.


Homework Equations



[tex]\Delta[/tex]Q/[tex]\Delta[/tex]T=e[tex]\sigma[/tex]AT^4

[tex]\sigma[/tex]=5.67*10^-8

The Attempt at a Solution



59=(.38)(5.67*10^-8)(A)(3.2*10^3)^4

Use needed Algebra to solve for A and I get 2.61e-5, but it's not the right answer.
Can someone please tell me what I am doing wrong?
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,230
31
Your temperature 3.2*10^3°C is in Celsius, you need to convert it to Kelvin (K).
 
  • #3
gneill
Mentor
20,793
2,773
What temperature scale is implied by the Stefan-Boltzmann constant?
 

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