beta decay:The spectrum is continuous I think, It depends on the distribution of P, over the neutrino , electron , and the Nucleus.
But the energy is usually from several 100 Kev to Mev's
The beta decay spectrum is continuous. The electron has a maximum velocity determined by energy conservation. For neutron decay, the maximum electron energy is approximately given by E=M_n-M_p. Then v=p/E with p=\sqrt{E^2-m_e^2}~1-m_2^2/2E, which is close to but a bit
smaller than 1. (all in units with c=1)
For nuclear beta decay, put in the masses of the nuclei.
The alpha particle has a definite velocity. Its energy is the difference in masses of the initial and final nuclei. Then v is found as above, but a nonrelativistic approximation is usually good.
Hmm, I don't know how to use that equation since I know very little of particle physics. How would you approximate a normal velocity for an electron to be when it's released for example from an uranium-238?
U-238 emits an alpha particle with an energy of about 4 MeV, which is non-relativistic, so one can use the classical kinetic energy E = 1/2 mv2 to calculate a velocity. One could ignore the momentum lost (<2%) to the Th-234 daughter product.
On the other hand, a 1 MeV beta particle requires a relativistic correction to determine its speed.