1. The problem statement, all variables and given/known data -60/120 ^1/3 2. Relevant equations I've gone through my book, and I'm supposed to find a number that when multiplied by a perfect cube I can bring it out and then cancel with the division. Try as I might with my calculator, I can't find one. Am I doing this wrong? 3. The attempt at a solution I broke the numerator and denominator down and I got 2 X 2 X 3 X 5 for 60, and 2 X 2 X 2 X 3 X 5 for 120. The only number I can bring out of the denominator is 2 X 2 X 2 which allows me to bring out 8. There is no number that I can bring out of the numerator. So basically, I got to 2 X 2 X 3 X 5 ^1/3 divided by 2(3 X 5)^1/3 Ahhh...I think that by talking this through, I figured it out. Can you let me know if I've done it right? Can I cancel the 3 and 5 since they're both cube rooted? then that leaves me with 4^1/3 divided by 2? Edit: Ehhh...Tried doing this on another problem, and ran into issues, so I'm guessing that I did this wrong.