- #1

frankR

- 91

- 0

This problem is killing me.

So far the real thing I've been able to find is how long the sample has been dead:

t = ln(2 &lambda N

_{o})/lambda

N

_{o}= the initial number of radioactive nuclei

Can I get a hint?

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- Thread starter frankR
- Start date

- #1

frankR

- 91

- 0

This problem is killing me.

So far the real thing I've been able to find is how long the sample has been dead:

t = ln(2 &lambda N

N

Can I get a hint?

- #2

arcnets

- 508

- 0

- #3

frankR

- 91

- 0

Originally posted by arcnets

rate. Now, you know that the disintegration rate has gone down from 15.0 to 0.03. How many half-lifes did that take?

That's an interesting way to look at the problem.

I'll see what I can do with that.

Thanks

- #4

frankR

- 91

- 0

I get:

t = 1.62 x 10^{12}s

Is this correct?

Thanks

Edit:

Which is 51374 years.

I just looked up how old C-14 dating is good too. It said 50,000 years. So it looks like I'm right.

This problem was easy, I don't know why I struggled with it so much!

t = 1.62 x 10

Is this correct?

Thanks

Edit:

Which is 51374 years.

I just looked up how old C-14 dating is good too. It said 50,000 years. So it looks like I'm right.

This problem was easy, I don't know why I struggled with it so much!

Last edited:

- #5

arcnets

- 508

- 0

Yes.Originally posted by frankR

Is this correct?

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