Radioactive decay: U-238 undergoes Alpha and Beta decays and becomes Pb-206

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Kim_Jong
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Homework Statement:
Consider a nuclear process in which U-238 undergoes several Alpha and Beta decays and becomes Pb-206. How many Alpha and Beta decays occur in this process?
Relevant Equations:
.
Alpha particle has two protons and neutrons so mass = 4.

4x = 238 -206.

x = 1/4(238-206) = 8 Alpha decays.

How would I determine the number of Beta decays? Since the mass doesn't change here.
 

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  • #2
How many protons are left if you do all the alpha decays first?
 
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  • #3
Kim_Jong
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76. So there will be 6 Beta decays.
 

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