- #1

Kim_Jong

- 2

- 0

- Homework Statement:
- Consider a nuclear process in which U-238 undergoes several Alpha and Beta decays and becomes Pb-206. How many Alpha and Beta decays occur in this process?

- Relevant Equations:
- .

Alpha particle has two protons and neutrons so mass = 4.

4x = 238 -206.

x = 1/4(238-206) = 8 Alpha decays.

How would I determine the number of Beta decays? Since the mass doesn't change here.

4x = 238 -206.

x = 1/4(238-206) = 8 Alpha decays.

How would I determine the number of Beta decays? Since the mass doesn't change here.

#### Attachments

Last edited by a moderator: