1. Oct 28, 2014

### desmond iking

1. The problem statement, all variables and given/known data
the variation of nuclear binding energy per nucelon of nuclei P , Q , R and S are shown.
Which process most likely to occur?

the ans is P to Q ... why not S to R ?

both
P to Q and S to R involve formation of unstable nucleus to more stable nucleus....

2. Relevant equations

3. The attempt at a solution

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2. Oct 28, 2014

### henxan

1. Radioactive decay is the process fission. What will this do with the number of nucleons?
Your answer to this should tell you which way any likely reaction would go, either:
• S $\rightarrow$ R and Q $\rightarrow$ P.
• S $\leftarrow$ R and Q $\leftarrow$ P.
2. To achieve a more stable atom, that is a resulting atom with a higher binding energy, which way will the respective reactions go?

As soon as you know the answer to these two conditions, only one possible option will remain :)...

H.

Last edited: Oct 28, 2014
3. Oct 29, 2014

### desmond iking

To achieve more stable atom either p to q or r to s will occur....

4. Oct 29, 2014

### desmond iking

Buy why the ans is p to q ?

5. Oct 29, 2014

### henxan

I think you need to read my previous reply a bit more careful ;)..

Both 1. and 2. Has to be fulfilled.. Also, your statement about stability, are both correct? Remember, higher binding energy $\rightarrow$ more stable.

6. Oct 29, 2014

### nasu

Do the problem actually mentions "radioactive decay"?
How is a decay in which the number of nucleons increases?