(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Hi,

The question itself doesnt sound too complicated i some-how got the asnwer,just wondering if its correct or not.

Question is:A radioactuve isotope wuith a half-life of 1.6x10^5 s disintegrates to form a stable product.A pure sample of 'x' is prepared with an initial activity of 25000Bq.

Caclulate the activity of the sample after week one.

2. Relevant equations

A= Ao e^-lamdba (t)

T(1/2)= Ln2 /lamda.

3. The attempt at a solution

I used initial activity as 25k bq now i thought activity to be in /s? i dont know here is what i've done.

A= Ao e^-lamdba (t)

LnA = LnA0 - (lamda)x T

LnA = ln(25000)-(4.33x10^-6 x 604.8x10^3)

A = 1822. <--- would the units be in s^-1?

Again thanks for your input =}.

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# Homework Help: Radioactivty: Activity?

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