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Radius and Interval of convergence
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[QUOTE="Painguy, post: 4378840, member: 352732"] [h2]Homework Statement [/h2] Ʃ(((-1)^n)(x^n))/(n+1) from 0 to ∞[h2]Homework Equations[/h2] [h2]The Attempt at a Solution[/h2] I took applied the ratio test and got that lim|(x^(n+1))/(n+2) * (n+1)/(x^n)| =|x| so that means for it to converge |x|<1 Radius of convergence is 1 My interval is (-1<x<1) Now I check the endpoints x=1 Ʃ(((-1)^n))/(n+1) from 0 to ∞ I want to use the alternating series test, but I have run into a little problem. I know that the Lim 1/(n+1) =0 but how do I prove that 1/(n+2) < 1/(n+1) for all n. I know its true, but my professor wants us to show that. I can show that -1<1 which is a true statement, but what does that say about the inequality in relation to n? Is there a better test to do this? Ratio test just equals 1 so that tells me nothing. I can't really use the integral test for an alternating series since it would end up imaginary. If there is a better test could someone still show how to use the alternating series if possible? [/QUOTE]
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Radius and Interval of convergence
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