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**[SOLVED] radius of a circle from refracted light in water**

**1. Homework Statement**

A swimmer at the bottom of a pool 4 m deep looks up and sees a circle of light. If the index of refraction of the water in the pool is 1.33, find the radius of the circle.

**2. Homework Equations**

[tex]\theta[/tex] (c) = Arcsin(n[tex]_{2}[/tex]/n[tex]_{1}[/tex])

n(1)*sin[tex]\theta[/tex](1) = n(2) * sin[tex]\theta[/tex](2)

**3. The Attempt at a Solution**

I used to first equation to find the angle of incidence, then used snell's law to calculate the angle of refraction. After which I am unsure of the correct way to proceed. I tried setting tan[tex]\theta[/tex] = 4/x, where I was using x as the radius, but I am pretty sure that it is not correct.