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Radius of a circle from refracted light in water

[SOLVED] radius of a circle from refracted light in water

1. Homework Statement
A swimmer at the bottom of a pool 4 m deep looks up and sees a circle of light. If the index of refraction of the water in the pool is 1.33, find the radius of the circle.


2. Homework Equations
[tex]\theta[/tex] (c) = Arcsin(n[tex]_{2}[/tex]/n[tex]_{1}[/tex])
n(1)*sin[tex]\theta[/tex](1) = n(2) * sin[tex]\theta[/tex](2)


3. The Attempt at a Solution
I used to first equation to find the angle of incidence, then used snell's law to calculate the angle of refraction. After which I am unsure of the correct way to proceed. I tried setting tan[tex]\theta[/tex] = 4/x, where I was using x as the radius, but I am pretty sure that it is not correct.
 

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