- #1
Oribe Yasuna
- 43
- 1
Homework Statement
A lead nucleus contains 207 nucleons (82 protons and 125 neutrons) packed tightly against each other. A single nucleon (proton or neutron) has a radius of about 1 ✕ 10^−15 m.
(a) Calculate the approximate radius of the lead nucleus.
(b) Calculate the approximate radius of the alpha particle, which consists of 4 nucleons, 2 protons and 2 neutrons.
(c) What kinetic energy must alpha particles have in order to make contact with a lead nucleus?
Homework Equations
v_sphere = 4/3 pi r^3
r_nucleon = 1 * 10 ^ -15 m
The Attempt at a Solution
207 * 1 * 10 ^ -15 m
2.07 * 10 ^ -13 m
Beyond this, I don't have any idea what to do.
I considered using d = m/v, but stopped halfway because I was approaching a bizarre answer.