1. May 6, 2009 #1

   imdapolak

   

   1. What are the radius and center of this circle? x^2+4x+y^2-3y=0
   
   
   
   2. Relevant equations
   
   
   
   3. Another question on my final review I dont recall exactly how to set up or what steps I need to do in order to solve this problem. Any help is appreciated

    

   imdapolak, May 6, 2009
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3. May 6, 2009 #2

   gabbagabbahey

   

   Homework Helper

   Gold Member

   If I gave you the equation in the form [itex](x-a)^2+(y-b)^2=r^2[/itex], could you tell me the location of the center of the circle and its radius?
   
   If so, just complete the square for both x and y in your above equation in order to get it into this form.

    

   gabbagabbahey, May 6, 2009
4. May 6, 2009 #3

   Cyosis

   

   Homework Helper

   The equation of a circle is of the form (x-a)^2+(y-b)^2=r^2. So you want to write x^2+4x as (x-a)^2+constant. In other words complete the square.

    

   Cyosis, May 6, 2009

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