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**[SOLVED] Radius of Convergence**

**1. Homework Statement**

1/(1+x^2) = sum ( (-1)^k*x^(2k) ; 0 ; inf) - A

integrating

arctan (x) = sum ((-1)^k * x^(2k+1) / (2k+1) ; 0; inf) B

I know A has radius of converge of 1, and I calculated B to be 2.

My assignment solution says "Similarly, the series for 1/(1+x^2) has R = 1 and integrating does not affect this. so R for atan (x) series is 1"

Obviously, they are wrong . Right?

Thanks.