- #1
pkossak
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A rock is dropped from outer space (initial velocity=0)
at a radius R from Earth's center. It is recorded moving at a
speed 8368 m/s when it strikes the surface of the Earth. What
was R? (in m) (Ignore the air resistance felt during the last
few miles of the approach to the planet) R Earth = 6.38*10^6
m, M Earth = 5.98*10^24. (in m)
Not sure about what equation to even start with. Was thinking about
g = (G*M earth)/r^2, but don't know what g is, and I don't see how I can find out without being given a time frame. Anyone know? thanks a lot
at a radius R from Earth's center. It is recorded moving at a
speed 8368 m/s when it strikes the surface of the Earth. What
was R? (in m) (Ignore the air resistance felt during the last
few miles of the approach to the planet) R Earth = 6.38*10^6
m, M Earth = 5.98*10^24. (in m)
Not sure about what equation to even start with. Was thinking about
g = (G*M earth)/r^2, but don't know what g is, and I don't see how I can find out without being given a time frame. Anyone know? thanks a lot