Radius of Gyration? REALLY need help ASAP!!! Hey - :surprised If any of you can help me with the following problem asap that would be awesome!! A racquet consists of uniform lamina that occupies the region inside the right-hand loop of r^2 = cos 2theta on the end of a handle (assumed to be of neglible mass) corresponding to the interval -1<=x<=0. Find the radius of gyration of the racquet around the line x = -1. Where is its sweet spot? I know the radius of gyration around the y axis can be found by the using the formula: radius of g = sqrt(Inertia around y axis / mass) Is this the correct formula for mass? m = int(0...pi/4)int (0...sqrt(cos2theta) r cos theta r dr dtheta? If so, how would revolving it around the line x = -1 instead of x = 0 change it? Thanks!