(adsbygoogle = window.adsbygoogle || []).push({}); Radius of Gyration? REALLY need help ASAP!!!

Hey -

:surprised

If any of you can help me with the following problem asap that would be awesome!!

A racquet consists of uniform lamina that occupies the region inside the right-hand loop of r^2 = cos 2theta on the end of a handle (assumed to be of neglible mass) corresponding to the interval -1<=x<=0. Find the radius of gyration of the racquet around the line x = -1. Where is its sweet spot?

I know the radius of gyration around the y axis can be found by the using the formula: radius of g = sqrt(Inertia around y axis / mass)

Is this the correct formula for mass?

m = int(0...pi/4)int (0...sqrt(cos2theta) r cos theta r dr dtheta?

If so, how would revolving it around the line x = -1 instead of x = 0 change it?

Thanks!

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# Radius of Gyration? REALLY need help

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