- #26

gneill

Mentor

- 20,795

- 2,773

It's a simple RC circuit where the capacitor is discharging through the resistor, so the current takes the form ##I_{max}e^{-t/\tau}##."I = (V/R)e^-0.25 = (10/5000)*(0.7788)=1.5576*10^-4=0.1557*10^-3=0.1557mA"

could someone clarify how to get "e^-0.25" from the above equation? and also "0.7788".

I dont understand the method thats being used here :-(

Thanks