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Radix r

  1. Feb 8, 2005 #1
    how do i find the radix r of equalities.
    for example how would i find the radix r of
    14r + 52r +3r =113r

    note:::: the r is a little subscribt on the bottom.
     
  2. jcsd
  3. Feb 9, 2005 #2
    Do you understand that the radix is the base being used to represent these numbers? In other words, that radix 10 means base 10 -- our common numbering system?

    The number 125 in base 10 can be broken down to
    [tex]1 \times 10^2 + 2 \times 10^1 + 5 \times 10^0[/tex]

    You can set up a system of equations to represent your equality in that form and solve them to discover the radix.

    PS: next time you should post your homework questions in the homework forum.
     
  4. Feb 9, 2005 #3
    ok then what would the r be in the above problem
     
  5. Feb 9, 2005 #4
    In my example, the "r" is 10.

    In your example, "r" is what you have to figure out. You don't want me to deny you all that fun, do you?

    I'll get you started, though. You have the number "113" in some base r. Let me see you write that number in the same format as I used to write my 125, only where I used 10, you use r.
     
  6. Feb 9, 2005 #5
    so 113=1X10^2 + 1X10^1 + 3X10^0 so in this case r also = 10.
    but how doe 14r +52r + 3r = 113r?

    im sorry for asking so many questions, but my prof literraly doent speak english and to top it off he stutters for about 5 sec on every word. and to top that off hes in his 80s.
     
  7. Feb 10, 2005 #6
    You missed my point. In your [itex]113_r[/itex], r is NOT 10.

    But just as I split up [itex]125_{10}[/itex] into a sum of powers of 10, you can split up [itex]113_r[/itex] into a sum of powers of r. And you can similarly split up the other numbers in your equation. See what you can do with that.
     
  8. Feb 10, 2005 #7

    mathman

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    (1*r+4)+(5*r+2)+3=1*r2+1*r+3

    Solve for r and make sure r>5.
     
  9. Feb 10, 2005 #8
    so would r be 6 or -1 in that case.
     
  10. Feb 10, 2005 #9
    Do you think it could be -1?
     
  11. Feb 11, 2005 #10

    HallsofIvy

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    14r + 52r +3r =113r[\sub]

    is exactly the same as
    r+ 4+ 5r+ 2+ 3= 1r2+ r+ 3 in base 10. Can you solve that for r?
     
  12. Feb 11, 2005 #11
    so in this example r is equal to 6 right
     
  13. Feb 11, 2005 #12
    Yeah, but do you understand the concept that just because -1 is one of the solutions to the quadratic equation doesn't mean that it is a valid solution to the problem you were solving?
     
  14. Feb 11, 2005 #13
    yes. Thanks to anyone who spent time helping me out. I really appericiate it. :smile:
     
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