- #1
Chronos000
- 80
- 0
I don't understand the following step:
using [tex]\hat{}a*[/tex][tex]\hat{}a[/tex] = ([tex]\hat{}H[/tex]/[tex]\hbar[/tex]w ) -1/2
<n|[tex]\hat{}a*[/tex][tex]\hat{}a[/tex]|n> = n<n|n>.
my first thoughts were to use a|n> = sqrt n | n-1> but I don't think that's relevant
if you sub in a*a and separate it into two expressions I don't see what good that would do
using [tex]\hat{}a*[/tex][tex]\hat{}a[/tex] = ([tex]\hat{}H[/tex]/[tex]\hbar[/tex]w ) -1/2
<n|[tex]\hat{}a*[/tex][tex]\hat{}a[/tex]|n> = n<n|n>.
my first thoughts were to use a|n> = sqrt n | n-1> but I don't think that's relevant
if you sub in a*a and separate it into two expressions I don't see what good that would do
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