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Raman spectroscopy question

  1. Jun 29, 2008 #1
    I read in a journal article that in raman spectroscopy "it is well
    known that signal yield increases with shorter wavelength". Can anyone please explain why? I would've thought longer wavelengths = shorter frequencies = higher susceptibilities?
  2. jcsd
  3. Aug 28, 2008 #2
    Sorry to bring this post up again, but I found the answer to my question if anyone is interested:
    Turns out the Raman process does NOT depend much on wavelength. It is the detection of the CCD's that have the highest quantum efficiencies in the visible.

    Between 600nm and 1000nm there is a 60% difference in detection efficiency.
  4. Oct 12, 2008 #3
    well the Raman process DO depent much on wavelengt (to the fourth power). And it's well understood.
    The fourth power can appear through a lengthy derivation using timedependent pertubation theory, second quantization of E-field and derivation of interaction between charges and E-field. You don't wanner mess with this.....
  5. Oct 12, 2008 #4
    Rayleigh Scattering depends on wavelength to the fourth power not Raman Scattering.
  6. Oct 12, 2008 #5
    Sorry to disapoint ya.
    Raman intensity DO varies with the fourth power of the observed frequency for normal Raman scattering, which, in turn, depends on laser frequency.
    It can be derived from the classical treatment of scattering from an oscillating induced dipole, with the intensity expressed in watts.

    Therefore, in biological Raman scattering one has to find a compromise between reduced fluorescence and reduced Raman signal by choosing bigger wavelength to obtain signals.

    In the full quantum picture it appears when you combine final density of states, laser intensity and scattered intensity with the Kramer Heisenberg equation

    You should note that modern Raman spectrometers,
    which usually measure photons/seconds rather than watts, are governed by a
    slightly different frequency dependence.
  7. Oct 12, 2008 #6
    I'm now confused :(

    Do you have any material I can refer too? In all the theory I've gone through I don't see any fourth power dependence. (haven't done QM though)

    Is it:
    Raman intensity varies with fourth power wavelength or,
    Raman intensity varies with fourth power frequency?

    Why are modern spectrometers different?
  8. Oct 13, 2008 #7
    This is a basic non QM practical guide
    "Raman Spectroscopy in Chemical Analysis wiley 2000"

    Raman intensity varies with fourth power of frequency
    and you know that [tex]c=\lambda*frequency[/tex]

    This is explained in "Raman Spectroscopy in Chemical Analysis wiley 2000"
    It's because there is a factor [tex]E=hv[/tex] in difference between watts and photon/sec
  9. Aug 21, 2010 #8
    hi, can you point me to a reference for the quantized field treatment? googling didn't help much, seems this is really a topic that not many are willing to touch.
    thx in advance
  10. Aug 21, 2010 #9


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    Science Advisor

    "Atom-photon interactions" by Cohen-Tannodji for instance?
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