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**1. Data**

Outer Diameter of tube=(64 +/- 2) and internal diameter= (47 +/- 1). Find cross-sectional area of tube and find percentage uncertainty.

Outer Diameter of tube=(64 +/- 2) and internal diameter= (47 +/- 1). Find cross-sectional area of tube and find percentage uncertainty.

**2. Equations**

## The Attempt at a Solution

I got (Delta A)/A = (Delta D2-d2)/(D2-d2) where D2-d2=1887 +/- 198. Hence my A= 1500 and my delta A is 157.

But the correct answer is 1500 +/- 300. And percentage uncertainty is 20%.

Can anyone give me the equations of the uncertainties??? For example there is another question about z=2x2 + y. Can you give me the equation? Im still very blur about this topic.