Random variable conditioning

  • Thread starter sneaky666
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Homework Statement



Let X and Y be jointly absolutely continuous Random Variables. Suppose X~Exponential(2) and that P(Y>5|X=x)=e-3x. Compute p(Y>5).


Homework Equations



X~Exponential(2) means that its a exponential distribution integrated from -inf to inf, then sub lambda as 2.

The Attempt at a Solution




the answer is 2/5 which is given but i dont get that... here is my prof's solution somehow he got 2/5
http://i.imgur.com/PCgDI.jpg

I don't understand how to get it, i end up getting infinity in the last step
 
Last edited:

Answers and Replies

  • #2
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nvm i figured it out
 

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