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## Homework Statement

On Earth you are able to consistently hit a golf ball 156 meter when you use your 5 iron which launches the ball at a 23 angle with respect to the ground. If you were to perform this same shot on the surface of an unknown planet called x, and

__be able to hit the ball 200 m__, what will be the acceleration due to gravity on the surface of the planet x?

My confusion is that I have somehow ended up with three range formulas and I don't know what the difference between them is:

## Homework Equations

R1 = V

_{o}

^{2}sin(2θ)/g

R2 = V

_{o}

^{2}sin(2θ)/2g

I also have my textbook saying:

h = V

_{o}

^{2}sin

^{2}(2θ)/2g

V

_{o}= initial velocity

## The Attempt at a Solution

156 meters = V

^{2}

_{o}sin(46)/(2*9.8)

V

_{o}= 65.1964 m/s

Then solving for g on planet x I get the answer as 7.644 which is the correct answer.

What confuses me is the difference between the formulas. Are two of them wrong or are they applicable in different circumstances?

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