On Earth you are able to consistently hit a golf ball 156 meter when you use your 5 iron which launches the ball at a 23 angle with respect to the ground. If you were to perform this same shot on the surface of an unknown planet called x, and be able to hit the ball 200 m, what will be the acceleration due to gravity on the surface of the planet x?
My confusion is that I have somehow ended up with three range formulas and I don't know what the difference between them is:
R1 = Vo2 sin(2θ)/g
R2 = Vo2 sin(2θ)/2g
I also have my textbook saying:
h = Vo2 sin2(2θ)/2g
Vo = initial velocity
The Attempt at a Solution
156 meters = V2osin(46)/(2*9.8)
Vo = 65.1964 m/s
Then solving for g on planet x I get the answer as 7.644 which is the correct answer.
What confuses me is the difference between the formulas. Are two of them wrong or are they applicable in different circumstances?