Range Formula

  • #1
ThomasMagnus
138
0
For a kinematics question, I am using the range formula:

R=(Vo^2)(Sin2(theta))/(g)

With my values in the equation I get: Square root of((7.80)(9.80)/(Sin2(28))
The correct answer is 9.60. I can't seem to get this answer. I believe it is the "Sin2(28)" part. What does this mean? Does this mean sin56? 2xsin28? Would you be able to explain what this means?

Thanks!
 

Answers and Replies

  • #2
gneill
Mentor
20,945
2,886
It means,

[tex] Range = \frac{V_o^2 \; sin(2 \theta)}{g} [/tex]
 
  • #3
ThomasMagnus
138
0
Sorry, I'm having trouble understanding. This kind of set up is new to me. I can't seem to get the correct answer when I plug it into my calculator. Does it have anything to do with the calculator being in radian or degree mode?

Thanks!
 
  • #4
ThomasMagnus
138
0
When I do it, I get 8.84, but the correct answer is supposedly 9.60
 
  • #5
ThomasMagnus
138
0
What I am asking is: how do you evaluate sin2(28)?

Thanks
 
  • #6
gneill
Mentor
20,945
2,886
What I am asking is: how do you evaluate sin2(28)?

Thanks

sin(2 * 28 degrees) = 0.829
 
  • #7
ThomasMagnus
138
0
sin(2 * 28 degrees) = 0.829

What would be the keystrokes for the calculator?

Thanks!
 
  • #8
ThomasMagnus
138
0
Wait I got it :)

Sin(2x28)=0.829

Thanks for the help!
 

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