# Range of P(x)

1. Oct 2, 2011

### Wa1337

1. The problem statement, all variables and given/known data
P(x) = √6+5x-x2

2. Relevant equations

3. The attempt at a solution
P(x) = √6+5x-x2

-x2+5x+6 >/= 0
x2-5x-6 </= 0
(x-6)(x+1) </= 0

2. Oct 2, 2011

### SammyS

Staff Emeritus
Do you mean $P(x) =\sqrt{6+5x-x^2}\,?$

If so, then use parentheses to make things clear.

P(x) = √(6+5x-x2).

Otherwise it looks like you have $P(x) =(\sqrt{6})+5x-x^2\,?$

What you have done will allow you to find the domain of P(x).

To find the range, find the vertex of the parabola of f(x) = 6+5x-x2 . Then proceed from there.

3. Oct 2, 2011

### Wa1337

In vertex form it is y=(x-2.5)2-12.25